2x^2+56x=1920

Solution for 2x^2+56x=1920 equation:

2x^2+56x=1920

We move all terms to the left:

2x^2+56x-(1920)=0

a = 2; b = 56; c = -1920;
Δ = b2-4ac
Δ = 562-4·2·(-1920)
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18496}=136$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-136}{2*2}=\frac{-192}{4}
=-48
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+136}{2*2}=\frac{80}{4}
=20
$